9y^2+41y-20=

Solution for 9y^2+41y-20= equation:

Simplifying
9y2 + 41y + -20 = 0

Reorder the terms:
-20 + 41y + 9y2 = 0

Solving
-20 + 41y + 9y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-5 + -1y)(4 + -9y) = 0

Subproblem 1
Set the factor '(-5 + -1y)' equal to zero and attempt to solve:

Simplifying
-5 + -1y = 0

Solving
-5 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1y = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1y = 0 + 5
-1y = 0 + 5

Combine like terms: 0 + 5 = 5
-1y = 5

Divide each side by '-1'.
y = -5

Simplifying
y = -5
Subproblem 2
Set the factor '(4 + -9y)' equal to zero and attempt to solve:

Simplifying
4 + -9y = 0

Solving
4 + -9y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -9y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -9y = 0 + -4
-9y = 0 + -4

Combine like terms: 0 + -4 = -4
-9y = -4

Divide each side by '-9'.
y = 0.4444444444

Simplifying
y = 0.4444444444
Solution
y = {-5, 0.4444444444}